We ar living in an era of overflowing chargers
1) What is Volt (V) / Amp (A) / Watt (W)?
In an era when various electronic devices are overflowing, we need to know how to calculate volts (V) / amps (A) / watts (W). When purchasing various electronics on the Internet, they ask us to use a charger of more than 20 watts, but we don't know what it is. And only bolts and amps are located on the charger.
First, a bolt is a unit of tangential pressure. It tells you how much electricity works, and it is a standard voltage unit for all figures, such as 220 volts in Korea and 110 volts in the United States.
The second is the ampere. Amp is a unit of electricity that flows over the same period of time.
The third is Watt. The most basic wattage in a unit of power is the amount of work done by electricity per unit of time that does one joule (J) per second.
The concept is the same as above, but we do not have to live by memorizing all of the concepts of the above electrical warfare. What we need, so how do we calculate watts? It is. A typical USB outlet does not have watts, only amps and bolts. And the calculation method for calculating watts is as follows.
W = V * A, i.e. watt = volt * ampere
From the left, if you do 5v * 3A, it becomes 15w.
On the rightmost side, if you do 12v * 1.5A, you get 18w.
It is a charger that supports up to 18w
It is 250V at 16A. Multiply the two by 4000 W
2) If you look at the example of calculating
If one outlet is 3 amps for 5 volts, the outlet supports up to 15 watts. If it says 5V/3A or 9v/2A, it may output 15W or 18W depending on the situation. It can be considered as an outlet that supports up to 18W.
With such a simple calculation method, I can buy an outlet that fits my device. And it is better to purchase a product with a W that is a little higher than the required limit of the device. In particular, in the case of multi-outlets, there is a risk of fire if they meet the wattage required by the device or connect to a multi-outlet with a wattage lower than the requirement. Therefore, avoid low-cost outlets as much as possible and have multi-outlets that provide more than 4000 W of output.
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